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本帖最后由 woaishuijia 于 2011-7-21 05:43 编辑 ! k8 [) p" |$ l+ T# n
d/ K$ l5 k0 P8 v9 U) O7 T用VBa做了个简单的小程序,居然提示“无效的过程调用或参数”# v' x4 b) T: ~9 C! @
程序:
; o! r! s2 f8 K0 \! g- Public Sub HTT()* ^" d6 K7 l2 g6 w4 H
- Dim Pt0, PT00 As Variant2 Z7 L' {. f3 U9 `
- Dim PT1(0 To 2), PT2(0 To 2), PT3(0 To 2) As Double
7 @, j D l# y1 G, D' x; Z - Dim L0, L1 As Double9 W% A, T E, i' M0 g8 m
- Dim i, m, n As Integer
9 T; c5 F) |( @: v5 K9 D2 h# M/ J0 @ - Dim ALine As AcadLine. G5 B6 p! t6 W1 I" d& ?
- Pt0 = ThisDrawing.Utility.GetPoint(, "基点:"); P, Z7 O4 W6 `! n3 R* |; x+ E
- X1 = Pt0(0)
& L8 X- G Q+ K - Y1 = Pt0(1)
! `/ ~! {2 @( |/ B4 t - L0 = ThisDrawing.Utility.GetDistance(, "单节筒节宽度:")
; ]1 X8 M% }' ` - L1 = ThisDrawing.Utility.GetDistance(, "筒节直径:")
2 D9 C3 w0 E* Z - PT1(0) = Pt0(0) + L1% c$ m/ _0 O+ b6 T$ x/ M* y9 t4 j
- PT1(1) = Pt0(1)
5 K( c- f% i n - PT1(2) = Pt0(2)
( x6 @( W6 ~3 l# a - PT2(0) = Pt0(0) + L1
6 q- k8 m! [1 e6 M r* F& |/ m5 e6 U3 n - PT2(1) = Pt0(1) - l27 Q: M. h. s# u! \+ j3 O( ^# i9 Q
- PT2(2) = Pt0(2)% f* m( S% {1 ]# N) q
- PT3(0) = Pt0(0)/ p) f/ Q) D" t, f; E# S: Q5 U
- PT3(1) = Pt0(1) - l2
, G. u0 O% }. O& k; w3 ~ - PT3(2) = Pt0(2)7 m' h o6 U. } y* }- L
9 ]1 v% M6 M% n# ^- N2 V; B: X: c2 _- Set ALine = ThisDrawing.ModelSpace.AddLine(Pt0, PT1)
1 W: q9 Y% G: L& c. p - Set ALine = ThisDrawing.ModelSpace.AddLine(PT1, PT2)
/ }) }$ i# b E - Set ALine = ThisDrawing.ModelSpace.AddLine(PT2, PT3)
/ ] E5 a5 K, c. c: g5 | - Set ALine = ThisDrawing.ModelSpace.AddLine(PT3, Pt0)! q3 @+ _ ^8 F" Y
- ZoomAll1 G: q3 ^, U* _# u
- End Sub
复制代码
. V( K1 Z7 X% j8 s/ K2 S; c错误提示:
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( Y/ ^7 r( \4 q2 X9 H4 E有知道如何解决的吗? |
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