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本帖最后由 woaishuijia 于 2011-7-21 05:43 编辑 ' q, I) }. o1 `+ I8 O
9 l5 J' ]$ _4 `) w; H* L9 Y, Y用VBa做了个简单的小程序,居然提示“无效的过程调用或参数”
. s. j" E. X! ] p9 f程序:$ X7 f+ g6 I v' w2 a
- Public Sub HTT(). ~: W, O# J# s- X( D
- Dim Pt0, PT00 As Variant) Z# O0 ]' s# {$ _/ l m
- Dim PT1(0 To 2), PT2(0 To 2), PT3(0 To 2) As Double
# d* ?4 g+ E+ O" K* d" q+ U6 c% I - Dim L0, L1 As Double
; K% w6 ~( H6 h$ t; A - Dim i, m, n As Integer0 v2 i0 c9 n# U3 v$ B$ H* l$ R
- Dim ALine As AcadLine
2 E( S* H5 ~4 f/ p& B4 y7 U - Pt0 = ThisDrawing.Utility.GetPoint(, "基点:"). {9 M1 Y) ~) p
- X1 = Pt0(0)4 W+ A2 [ u5 l) i
- Y1 = Pt0(1)4 U& z. C- U7 D
- L0 = ThisDrawing.Utility.GetDistance(, "单节筒节宽度:")' G# D$ g+ V& b
- L1 = ThisDrawing.Utility.GetDistance(, "筒节直径:")
" y8 }! S+ s* [4 Y - PT1(0) = Pt0(0) + L1
2 a, L7 s) t- |, _4 }2 r4 }5 A - PT1(1) = Pt0(1)0 U7 i" \1 I L6 p$ b
- PT1(2) = Pt0(2)
+ s" A. T. P/ Y9 {% g( C3 D ~% Z: o - PT2(0) = Pt0(0) + L1
5 V2 i8 E7 x" ^, A: r' Z8 j - PT2(1) = Pt0(1) - l2
$ a) Y7 P& M% m - PT2(2) = Pt0(2)
0 k. A7 H2 d) z1 o6 }" w - PT3(0) = Pt0(0)$ z3 ?2 R C" Y, {. \
- PT3(1) = Pt0(1) - l2
( o3 z4 ]3 m& k* }6 Q; F - PT3(2) = Pt0(2)8 J5 Z7 V% r! W8 e* u( Q
2 ?. D& v! z4 { L: r* I- Set ALine = ThisDrawing.ModelSpace.AddLine(Pt0, PT1)+ p5 H Z- y' I
- Set ALine = ThisDrawing.ModelSpace.AddLine(PT1, PT2)1 j4 ]- z- C3 q" h
- Set ALine = ThisDrawing.ModelSpace.AddLine(PT2, PT3) I$ I1 B8 O/ Q
- Set ALine = ThisDrawing.ModelSpace.AddLine(PT3, Pt0)6 F1 z' O0 u6 a) C0 |; \1 l, b0 g
- ZoomAll7 d- d/ P8 K4 W4 P: g
- End Sub
复制代码
" h: [9 A5 ?$ q3 b" v0 I6 h7 I错误提示:9 ]( @0 G2 w0 c' Q; @/ s3 u& D8 J. {
Z. u7 g+ |5 E2 p0 P: }
有知道如何解决的吗? |
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