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UID396100
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在线时间 小时
注册时间2007-10-17
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发表于 2011-12-24 13:07:17
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来自: 中国山东青岛
工具 宏 打开VBA管理器$ I: @: k3 ~( q, V* h
插入模块 复制如下 运行 即得渐开线 有了渐开线 齿轮不就出来了吗$ ^5 ]7 V( v8 ]6 f% O
Sub jkx(); b: \& f% D1 m0 `, M0 O) z% e
Rem 绘制渐开线,2 ^3 l3 @+ ?+ }
Dim d As Double '节圆直径2 h% L Q6 X" ~8 K
Dim r As Double '节圆半径
4 U: ]' @ c6 [: t- `+ xDim A As Double '总展开角度
: V5 E x, P% ]# \# \* rDim Ai As Double '展开角度
* }8 {0 ?/ `! i$ Z6 y8 BDim Li As Double '展开弧长
9 i, P7 [' A4 L! ~: M' u. R- \d = 100
5 |% F9 ]: v( x/ Z8 ^3 h1 X2 g! }' BA = 360
2 B* I% v+ E- z8 ?& ir = d / 2
5 E4 P& i* I8 G, s) c) O% QDim Pnt1(2) As Double
5 E! j M. ^# d/ R* G1 \7 V, tDim Pnt2(2) As Double- G6 Y2 e# i" F3 s4 ~4 H
Dim PntLst() As Double, N As Integer( p! W( F# Q; f3 `* ^1 j
ThisDrawing.ModelSpace.AddCircle Pnt1, r A9 i5 P7 S5 h [0 [1 W
For Ai = 0 To A * Atn(1) / 45# Step Atn(1) / 45#
5 x. L5 k N4 v: \; X: Z) y: ~$ }Li = r * Ai
1 I. o/ ~( ?3 b3 R" KPnt1(0) = r * Sin(Ai)$ { L. ~& B9 ?0 }+ v- n
Pnt1(1) = r * Cos(Ai), U K, j/ y6 _. r! F8 y
Pnt2(0) = Pnt1(0) - Li * Cos(-Ai)
. X. h9 z) g1 aPnt2(1) = Pnt1(1) - Li * Sin(-Ai)
0 S8 b7 @3 l5 v. ~ThisDrawing.ModelSpace.AddLine Pnt1, Pnt2' ?8 x0 `: b t# o' f5 A& v
N = N + 1/ V | k- ^ p
ReDim Preserve PntLst(N * 2 - 1)5 @9 Z% ?6 ` n9 I/ y
PntLst(N * 2 - 2) = Pnt2(0)' s j7 T& e! q, X, O2 q! h
PntLst(N * 2 - 1) = Pnt2(1), Q6 a7 }5 f& T" S! `
Next, I; k# s- y3 w e( D! t
If N > 1 Then
; t o# R- ~; gThisDrawing.ModelSpace.AddLightWeightPolyline PntLst
+ b$ v! g& j- P. CEnd If) p0 ^" ]( e) `8 D7 a. v& {
End Sub |
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