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UID396100
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注册时间2007-10-17
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发表于 2011-12-24 13:07:17
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来自: 中国山东青岛
工具 宏 打开VBA管理器# n/ ?9 t+ E+ N; i- {
插入模块 复制如下 运行 即得渐开线 有了渐开线 齿轮不就出来了吗
; E# p& k" @2 i2 f8 xSub jkx()
# Y" I% J1 q! G3 dRem 绘制渐开线,! m9 V) Q- L( T) y7 ]
Dim d As Double '节圆直径
5 B( T O* N2 R3 Q" ~Dim r As Double '节圆半径
3 V# M" Y3 y7 y) J5 W) xDim A As Double '总展开角度: L, l* V7 A7 {7 z9 K9 _2 @
Dim Ai As Double '展开角度
7 O- J/ u" ~% J; H F: [Dim Li As Double '展开弧长
. W; F9 q9 @9 J. _$ g) n) A) ed = 100% ^- C/ r* G' b b
A = 3605 a0 f, J6 |7 c$ s
r = d / 21 |& H/ ]/ o- B# w1 k; z1 X: e
Dim Pnt1(2) As Double/ @6 A. h: r$ q. L9 R r7 w
Dim Pnt2(2) As Double
9 L+ E- N$ X& J* M% ~8 _+ YDim PntLst() As Double, N As Integer2 \. J$ I4 T5 Y7 }: u# a
ThisDrawing.ModelSpace.AddCircle Pnt1, r
: Y9 a" P. Y. _ \, [- mFor Ai = 0 To A * Atn(1) / 45# Step Atn(1) / 45#
# A" H4 Z, r8 u. P( j- F' K1 cLi = r * Ai
# G3 x7 W: }& x* p5 n6 QPnt1(0) = r * Sin(Ai)
1 ~( j& y& W- R2 ^! S' \Pnt1(1) = r * Cos(Ai)8 J! L1 n9 r1 q+ D# M8 ~2 |/ a
Pnt2(0) = Pnt1(0) - Li * Cos(-Ai)% \. t, }9 W6 |9 S: c% f3 w& W
Pnt2(1) = Pnt1(1) - Li * Sin(-Ai)
: b. p R. J% s3 d2 OThisDrawing.ModelSpace.AddLine Pnt1, Pnt28 }" |) q1 h: r! \
N = N + 16 C$ l0 I* Z; G& Q
ReDim Preserve PntLst(N * 2 - 1)
* q/ n# J, v* [; z% n; x( b: B# @; t1 cPntLst(N * 2 - 2) = Pnt2(0)1 ^. ]' h* G' |* J0 d) I
PntLst(N * 2 - 1) = Pnt2(1)+ D! x2 X; h* D- O H @: u
Next7 ?/ }1 \$ a$ |& _0 V, q
If N > 1 Then
. P$ m3 [* o7 X# Z) y& _) IThisDrawing.ModelSpace.AddLightWeightPolyline PntLst) o* M% ~& {& {
End If
6 j7 y# Z: F( O! }' a# I( VEnd Sub |
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