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发表于 2019-12-8 22:50:36
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来自： 中国吉林
以默认MPLFAN为例,搜索
* v6 y6 i( f$ E4 g% ]4 d( U% bpsgcode #Output the Gcode based on the current plane& g( i& q0 P; \9 G) N4 i2 l* h
找到代码# G7 M% X" _! I8 e1 |: ^
psgcode #Output the Gcode based on the current plane
8 }! W: l9 y) n/ d8 k6 h7 G if c_ax_flp,- m) w' e) j' @% A1 y5 U1 X
[: S3 D- C$ [2 g. h4 j
#Reverse arc direction for c_axis flip
) R2 e: Z& n0 b4 i7 S; n# \" L if gcode$ = two | gcode$ = three,# P0 Y( g5 F) J+ L6 l
[
5 \- d5 I ]) ?7 F6 e sav_gcode = gcode$
! X) [3 y( J% b9 G2 h gcode$ = (5 - gcode$) #G02->G03 or G03->G029 b' G0 K5 }0 Q. N* K3 s, _2 f7 A+ k
]
" [) v8 W. Z$ w( Z, ]) J9 {/ `6 M" q, d ]
8 }9 L3 b4 I% x* y if plane$ = zero, `sgcode
/ t# y2 f; K& T% L! ~, [/ j- j if plane$ = one, `sgcode19 m5 f, V$ p) b. n9 W" u
if plane$ = two, `sgcode2, s: f7 u3 }+ R9 f& a
if c_ax_flp, gcode$ = sav_gcode7 |" F! z9 [2 l; p0 g
! R2 P- b G1 M5 U% C
加点作料改为
( K! Q0 S; h! v8 Q! A# l/ F1 Spsgcode #Output the Gcode based on the current plane
2 X- t8 l C0 X7 s' o/ E8 W if c_ax_flp,, G% U' f/ t9 U
[3 _: F( ]+ C2 c5 M! W7 M& S
#Reverse arc direction for c_axis flip
5 x6 R+ l, o; f0 J0 C if gcode$ = two | gcode$ = three,
8 R/ a6 @# r" I) `: x0 b7 [ [
; I9 L5 x8 C8 R6 C sav_gcode = gcode$
5 z9 Q2 w2 ?' j gcode$ = (5 - gcode$) #G02->G03 or G03->G02
& d% c4 }0 |2 g& e' B ]. L3 w* n a3 X
]
5 b9 Z) P! Z F if gcode$ = 2 | gcode$ = 3, result = force(gcode$)
$ b, _ T+ c2 v+ a6 ^# k; b if plane$ = zero, `sgcode
& J. P: p( U$ ?/ X if plane$ = one, `sgcode1
) D9 W% o1 u% h" E( s) e- Z if plane$ = two, `sgcode2
; D3 C8 a/ J3 z; b$ T/ A) P if c_ax_flp, gcode$ = sav_gcode; f% G2 L+ [+ Z5 K' F4 B
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发表于 2019-12-8 13:42:50