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楼主 |
发表于 2016-3-11 15:51:37
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来自: 中国浙江嘉兴
0 E! `8 x* K- V5 l* _* J" Y+ Z至于用宏的方法,那里可以找到相关资料? 之前已分享不少了,若是不能吸收理解,就僅能抄襲無法廣用.0 z& ~* D! y8 A b
3 w8 q+ ]$ V8 W: K4 G. n; G如下參考
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' ****************************************************************************** K! ~# a K& k! l
' macro recorded on 03/04/16 by scliang0 B$ s7 u: Y% x# p2 p U! Q
' ******************************************************************************" _* I7 N+ m, M
Dim swApp As Object0 X" i' V% t# r {
Dim Part As Object
/ E: ` q- e/ T IDim boolstatus As Boolean6 D4 H9 l$ C+ [- \: G# r, T* ?
% k# r3 g0 U" F2 V7 S% QSub main()
+ i$ x: ?$ H9 ?6 z3 m4 N$ P+ O5 {7 ASet swApp = Application.SldWorks
: l3 K9 z" n$ P+ P& G* pSet Part = swApp.ActiveDoc" T! @. }" F/ c. Q6 d0 L. u
Set myModelView = Part.ActiveView
' W) U7 Q' B4 Q/ P& sDim myDimension As Object
( n; i) Q. r! o# O2 c: ppi = Atn(1) * 4. k8 _, v: x" ]
Set myDimension = Part.Parameter("D15@草圖1") '對應控制角度
$ G; ?: q G- q/ N* N# NFor i = 0.1 To 90.1 Step 5
* R' a' R0 O& @, NA = i * pi / 1800 ]7 R( c3 Z- `; K
myDimension.SystemValue = A
) G" J4 }# X& vboolstatus = Part.EditRebuild3()1 {' t" n& q8 ^+ G
myModelView.RotateAboutCenter 0, 01 O! J- Z6 p/ g( y- x' K; h0 Z
Next' ^; V0 h4 G) @$ k5 x Z
For i = 85.1 To 0.05 Step -5. O5 N: f3 W- ?2 p! G8 L
A = i * pi / 180
% v5 I% {6 ~# I1 qmyDimension.SystemValue = A
% q1 L) r$ L# Lboolstatus = Part.EditRebuild3()
/ _: _" t7 u8 { r U, jmyModelView.RotateAboutCenter 0, 0
: q6 h' l+ D- @4 \Next
$ X) `7 B, Z" \# _. |7 t" r% t. zEnd Sub5 b3 a- ~5 c, ]$ e6 I+ o! O* u
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Macro1.rar
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