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UID396100
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在线时间 小时
注册时间2007-10-17
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发表于 2011-12-24 13:07:17
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来自: 中国山东青岛
工具 宏 打开VBA管理器
! K0 G" f% J0 U" g- I/ G 插入模块 复制如下 运行 即得渐开线 有了渐开线 齿轮不就出来了吗
( X. r0 f% M* Y- {7 v6 {# B7 eSub jkx(). U& ^5 o! J' w, Q" t, x
Rem 绘制渐开线,
' d; h @0 d- n. w* EDim d As Double '节圆直径
& s% t0 B9 o2 Q5 k* Q' U4 ]Dim r As Double '节圆半径2 M' U2 e# f2 Q* o, N
Dim A As Double '总展开角度8 s. ?5 o! g8 D0 V7 O
Dim Ai As Double '展开角度
8 t7 ]( t8 U( M& M# h5 BDim Li As Double '展开弧长# U0 t: g: R+ V4 q$ w$ `. [' }2 i/ f
d = 1000 C: h. ^: i5 L
A = 3602 x* r4 S% d) h0 c
r = d / 2
" a& f, p+ r( C( q9 p5 ^- L. |Dim Pnt1(2) As Double
! P+ E* b }4 Z/ ?Dim Pnt2(2) As Double$ i- I4 N" X, E3 j
Dim PntLst() As Double, N As Integer* G# I6 H- D- e/ w4 G3 n
ThisDrawing.ModelSpace.AddCircle Pnt1, r" i) R6 b4 Z: }' g% B: M5 h0 Q. p
For Ai = 0 To A * Atn(1) / 45# Step Atn(1) / 45#
5 O# v/ E0 z" T, tLi = r * Ai
# U2 [/ _. o& aPnt1(0) = r * Sin(Ai)& o! x0 C* i. K; p& L( w4 _
Pnt1(1) = r * Cos(Ai), O8 R9 l2 `' c/ z: k2 Q
Pnt2(0) = Pnt1(0) - Li * Cos(-Ai)
* W. o5 F6 b2 o5 xPnt2(1) = Pnt1(1) - Li * Sin(-Ai)
6 K; x7 H, E0 y \: a# t( y0 G- ~! PThisDrawing.ModelSpace.AddLine Pnt1, Pnt27 M8 \- K2 ] K# w( R
N = N + 19 Q( r2 ]- c* Y- h0 B' @6 A
ReDim Preserve PntLst(N * 2 - 1)
) i0 k% X" B( O' B/ s4 OPntLst(N * 2 - 2) = Pnt2(0)9 s; T1 W Q, c6 M4 I* I
PntLst(N * 2 - 1) = Pnt2(1)
( g+ t% \5 c* b" X8 MNext5 [" P' F6 ?! n2 N7 a" R" p$ K
If N > 1 Then$ i8 b. N4 I8 Z
ThisDrawing.ModelSpace.AddLightWeightPolyline PntLst
1 M+ [/ | E4 L+ x% G* A% HEnd If
* Q O4 h5 V1 h6 M2 b9 h7 qEnd Sub |
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