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UID396100
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在线时间 小时
注册时间2007-10-17
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发表于 2011-12-24 13:07:17
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来自: 中国山东青岛
工具 宏 打开VBA管理器" b# @6 R- f1 X! A
插入模块 复制如下 运行 即得渐开线 有了渐开线 齿轮不就出来了吗0 x7 N+ C5 ]0 |( @, G, ^ y
Sub jkx()
# I! _8 a1 ] z& y3 M/ O3 L% qRem 绘制渐开线,
7 n! V% t, D: n4 UDim d As Double '节圆直径/ S4 H$ h, G% c+ T/ C
Dim r As Double '节圆半径
# J. e$ d1 s- B7 @, ^/ ADim A As Double '总展开角度0 l% X0 g" j1 R) d* B9 _2 D0 D" F
Dim Ai As Double '展开角度3 W$ j+ A- _; f* @% y( R; g' X Z
Dim Li As Double '展开弧长
, d. K8 R1 H, g8 _d = 100
4 l* E) y- [7 ~2 X3 `. J _' b jA = 360
% C7 N! k9 t4 o, Mr = d / 2+ S! n4 i0 ~6 s& U) h j: e7 t
Dim Pnt1(2) As Double
. |7 o7 ?$ h; q: [; s9 d* aDim Pnt2(2) As Double
4 R8 }6 f+ f* y% @- r& g. RDim PntLst() As Double, N As Integer
1 S* |( P7 P* a( LThisDrawing.ModelSpace.AddCircle Pnt1, r
( U" m" L3 V6 n& V. b, U I& WFor Ai = 0 To A * Atn(1) / 45# Step Atn(1) / 45#7 T" s& v( `' U$ ?& i7 \
Li = r * Ai
5 l v. I) @* O& c$ MPnt1(0) = r * Sin(Ai)! h" [! P1 x, }- g( o
Pnt1(1) = r * Cos(Ai)& M: n+ z. h# @! _$ j0 {
Pnt2(0) = Pnt1(0) - Li * Cos(-Ai)5 {% k0 N: g! O1 L
Pnt2(1) = Pnt1(1) - Li * Sin(-Ai)
+ L! Q4 I" C: E9 W0 Q5 tThisDrawing.ModelSpace.AddLine Pnt1, Pnt22 n1 j% Y7 c9 r2 ~. z. z
N = N + 16 ]/ [. c% W0 G
ReDim Preserve PntLst(N * 2 - 1)
- M, C& [5 \# n% M! j# z) o! yPntLst(N * 2 - 2) = Pnt2(0)
1 Y3 Q. g/ {. [PntLst(N * 2 - 1) = Pnt2(1)
0 Y$ y$ Y i9 M$ j3 S* J7 {7 V8 SNext: s# I) @/ _; P$ d9 q9 i5 y
If N > 1 Then! l. ?) q" a8 @6 U: m8 q# I
ThisDrawing.ModelSpace.AddLightWeightPolyline PntLst( @/ d; P1 d1 z5 @
End If
+ o( c' Q* D* F7 f- c! M6 CEnd Sub |
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