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UID396100
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在线时间 小时
注册时间2007-10-17
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发表于 2011-12-24 13:07:17
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来自: 中国山东青岛
工具 宏 打开VBA管理器" `4 ~( F" D' b2 z! h8 ~. E7 Q
插入模块 复制如下 运行 即得渐开线 有了渐开线 齿轮不就出来了吗& o7 `7 q( j' t+ f0 w |
Sub jkx()! ?3 W8 k, _# ]
Rem 绘制渐开线,$ d6 \4 P& _7 H6 D# D& t6 J
Dim d As Double '节圆直径
" w3 k) `) ]& L' v" p0 j/ rDim r As Double '节圆半径4 e' ?" W1 G- w; q; K, M$ `" M
Dim A As Double '总展开角度
- x$ n" ~ p5 [Dim Ai As Double '展开角度
. ?: M( V5 E/ U# w/ vDim Li As Double '展开弧长
3 ?3 E4 O; F: v8 {8 {d = 100& ~; t! c1 f$ a5 }" b
A = 3606 l1 J9 |; l `( w, ]) {$ C5 c. l
r = d / 2, J. h: F& |5 \
Dim Pnt1(2) As Double, s( w7 F$ `1 @* R0 ~+ F
Dim Pnt2(2) As Double. Z/ i' p9 Z$ q$ D
Dim PntLst() As Double, N As Integer; }' \ J% w2 H0 S, f A: m4 ]
ThisDrawing.ModelSpace.AddCircle Pnt1, r
& U5 U- Z. v6 h, B B( EFor Ai = 0 To A * Atn(1) / 45# Step Atn(1) / 45#( e0 I8 @' D$ ?' i7 X: A+ }
Li = r * Ai
7 F; n4 b2 N* j3 U: O/ ~- ^Pnt1(0) = r * Sin(Ai)
' S. p# P! S, ~( N* {* NPnt1(1) = r * Cos(Ai)
$ i& f |3 h) C# jPnt2(0) = Pnt1(0) - Li * Cos(-Ai)1 \3 Q6 b8 B4 n0 ]4 K
Pnt2(1) = Pnt1(1) - Li * Sin(-Ai)
3 q' |- \) {) L3 H0 M9 nThisDrawing.ModelSpace.AddLine Pnt1, Pnt2
. M: ~2 [ T, X- k( C/ Q1 yN = N + 1
* r7 c' I" ]% V; pReDim Preserve PntLst(N * 2 - 1)
k9 ]9 j R' E1 p2 S& cPntLst(N * 2 - 2) = Pnt2(0)
o, ~5 o. J! F% l! m; ?1 nPntLst(N * 2 - 1) = Pnt2(1)
% d/ } ]" {; y' TNext6 D1 X9 A1 e7 t, O, S: y- x
If N > 1 Then
6 C p' e" \1 f' r+ vThisDrawing.ModelSpace.AddLightWeightPolyline PntLst) z c) G; j7 v4 w0 Y
End If5 z# T1 S5 r- b2 t, B
End Sub |
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