在二次开发中应用的公式超出范围？

nanyuchun

我把录制的程序改了下，如下：
Private Sub CommandButton1_Click()
; H' E* D, R, J# u2 sDim swApp As Object
6 L0 a* t9 q$ ^' c6 T* {Dim Part As Object
Dim SelMgr As Object
Dim boolstatus As Boolean
Dim longstatus As Long, longwarnings As Long
& N6 l6 c$ c4 J6 u/ eDim Feature As Object
Dim a As Double
# A: L$ W& T9 p* ^8 \3 S* \$ MDim b As Double
Dim c As Integer
% I5 R( j$ Z  s6 c( o& nDim r1 As Integer
Dim r2 As Integer
  Y3 Y7 ?/ @6 `0 S: vSet swApp = Application.SldWorks
Set Part = swApp.ActiveDoc
8 _8 Y9 K# C: z1 w4 K6 m& ?4 }* la = CDbl(TextBox1.Text) / 1000
1 p2 a' x1 u  e  f$ v; g- i/ Ab = CDbl(TextBox2.Text) / 1000
c = CDbl(TextBox3.Text) / 1000
r1 = CDbl(TextBox4.Text) / 1000
r2 = CDbl(TextBox5.Text) / 1000
Set SelMgr = Part.SelectionManager
4 M) Q, h: K( oboolstatus = Part.Extension.SelectByID2("前视基准面", "PLANE", 0, 0, 0, False, 0, Nothing, 0)
Part.InsertSketch2 True
/ k" L; ]" [5 ]: a! O1 o/ X) wPart.ClearSelection2 True
Part.CreateLine2(0, 0, 0, a, 0, 0).ConstructionGeometry = True
Part.CreateCircleByRadius2 0, 0, 0, r1
Part.ClearSelection2 True
$ v' {) i, V& V) |6 }/ gPart.CreateCircleByRadius2 a, 0, 0, r1
Part.ClearSelection2 True
, E- A6 ?! {' i1 Z6 M3 @Part.SetPickMode
Part.CreateLine2 Sqr(r1 ^ 2 - (b / 2) ^ 2), b / 2, 0, a - Sqr(r1 ^ 2 - (b / 2) ^ 2), b / 2, 0
# ^) a/ o9 V$ R/ E; [Part.SetPickMode
8 T- m  w# R2 Z0 P( ~$ ]Part.ClearSelection2 True
Part.CreateLine2 Sqr(r1 ^ 2 - (b / 2) ^ 2), -b / 2, 0, a - Sqr(r1 ^ 2 - (b / 2) ^ 2), -b / 2, 0
Part.SetPickMode
$ V  Y+ n+ a7 E' ]6 c+ IPart.ClearSelection2 True
Part.SetPickMode
$ Y" R$ P' r2 C! M4 H7 `boolstatus = Part.Extension.SelectByID2("圆弧1", "SKETCHSEGMENT", 0#, 0#, 0#, False, 0, Nothing, 0)
' G0 s, H8 b* \' y; ?. ~, `+ fPart.SketchManager.SketchTrim 0, Sqr(r1 ^ 2 - (b / 2) ^ 2), b / 2, 0
2 Q( b# D7 [7 F' i! q0 {4 j( ^Part.SetPickMode
' A, f. {: A6 F+ kboolstatus = Part.Extension.SelectByID2("圆弧1", "SKETCHSEGMENT", 0#, 0#, 0#, False, 0, Nothing, 0)
Part.SketchManager.SketchTrim 0, Sqr(r1 ^ 2 - (b / 2) ^ 2), -b / 2, 0
; z" O; M8 h7 tPart.SetPickMode
8 S* v6 b& V& @! F% P  ^# Jboolstatus = Part.Extension.SelectByID2("圆弧2", "SKETCHSEGMENT", 0#, 0#, 0#, False, 0, Nothing, 0)
Part.SketchManager.SketchTrim 0, a - Sqr(r1 ^ 2 - (b / 2) ^ 2), -b / 2, 0
6 ]8 k$ a% e/ ]) [7 Y: E- aPart.SetPickMode
boolstatus = Part.Extension.SelectByID2("圆弧2", "SKETCHSEGMENT", 0#, 0#, 0#, False, 0, Nothing, 0)
- d' W- a& X4 g3 }Part.SketchManager.SketchTrim 0, a - Sqr(r1 ^ 2 - (b / 2) ^ 2), b / 2, 0
Part.SketchManager.InsertSketch True
- V5 Z6 v2 R% [/ n& bboolstatus = Part.Extension.SelectByID2("草图1", "SKETCH", 0, 0, 0, False, 0, Nothing, 0)
Part.ShowNamedView2 "*上下二等角轴测", 8
% t/ v- }! D" S# A( g/ t1 l- {4 D, vPart.ClearSelection2 True
boolstatus = Part.Extension.SelectByID2("草图1", "SKETCH", 0, 0, 0, False, 0, Nothing, 0)
Part.FeatureManager.FeatureExtrusion2 True, False, False, 0, 0, c, 0, False, False, False, False, 0.01745329251994, 0.01745329251994, False, False, False, False, 1, 1, 1, 0, 0, False
Part.SelectionManager.EnableContourSelection = 0
! d  V9 @4 ^6 Q. P! x3 H' Lboolstatus = Part.Extension.SelectByID2("", "FACE", 3.123904942299E-04, -4.650735940004E-05, 0.01999999999987, False, 0, Nothing, 0)
Part.SketchManager.InsertSketch True
Part.ClearSelection2 True
: F4 j6 _. P- J) pPart.CreateCircleByRadius2 0, 0, 0, r2
; [1 r! o* j" IPart.ClearSelection2 True
4 s" |+ O( ]) a$ M- M4 ?Part.CreateCircleByRadius2 a, 0, 0, r2
Part.ClearSelection2 True
Part.SketchManager.InsertSketch True
, O2 J* @: ^& l' Q% bPart.SketchManager.InsertSketch True
Part.ClearSelection2 True
boolstatus = Part.Extension.SelectByID2("草图2", "SKETCH", 0, 0, 0, False, 0, Nothing, 0)
/ o  @$ \$ i7 Y  A0 A9 b0 H. QPart.FeatureManager.FeatureCut True, False, False, 1, 0, c, 0.02, False, False, False, False, 0.01745329251994, 0.01745329251994, False, False, False, False, 0, 1, 1
5 a" F, s  k6 B0 J9 BPart.SelectionManager.EnableContourSelection = 0
1 A, h0 d1 T; j) ]5 LEnd Sub
运行到这句：Part.CreateLine2 Sqr(r1 ^ 2 - (b / 2) ^ 2), b / 2, 0, a - Sqr(r1 ^ 2 - (b / 2) ^ 2), b / 2, 0时，报错，说数值超过范围或函数调用有误，这是什么原因呢，真心求教,谢谢！
7 b. b% i. L8 k2 C' `- a
( b+ [# m4 E3 w  x' i% y  j3 e[ 本帖最后由 nanyuchun 于 2009-5-10 09:19 编辑 ]

nanyuchun

自己坐沙发等回答。。。

nanyuchun

怎么就没人回答呢？

飞天鸟

最好先用一个变量储存上述公式的运算结果, 然后再调用函数. 这样, 调试时可以比较容易找到问题.

少来我可

Sqr(r1 ^ 2 - (b / 2) ^ 2)
5 E8 w4 j0 m" q2 g6 d# ur1 ^ 2 - (b / 2) ^ 2
可能这里出现了负数，你给负数求平方根，就出错了
) i2 O9 T% i8 @# M你可以加一句看看：MsgBox (r1 ^ 2 - (b / 2) ^ 2)