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发表于 2013-6-14 15:41:56
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来自： 中国广东广州
本帖最后由 topidea 于 2013-6-17 21:00 编辑 2 E* }5 [2 d! |: R. {3 O- I
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这还不简单吗? 将 acad.pat 及 acadiso.pat 文件打开，将下边这段加进去: N4 v/ P0 K, |9 E; |
* c6 Y* k8 O! D/ u$ N/ g+ s*钢筋混凝土, Tangent3 H& T: B/ S# V0 S
45 , 0 ,0,0, 2.55 [) L' J3 \6 Z' d7 B) @
50, 0,0, 4.12975034,-5.89789472, 0.75,-8.25) j4 ?: ^! d7 ]! I7 q7 e/ N" s
355, 0,0, -2.03781207,7.37236840, 0.60,-6.69 @ h) U- o; U6 D# @& f
100.4514, 0.5977168,-0.0522934, 5.7305871,-6.9397673, 0.6374019,-7.01142112
8 e" o0 R( i' Q( j46.1842, 0,2, 6.19462551,-8.84684208, 1.125,-12.375' x! k) \) ]1 u t0 |' |: y/ P
96.6356, 0.88936745,1.86206693, 8.59588071,-10.40965104, 0.95610288,-10.51713* x4 C4 S! @' T) k8 p
351.1842, 0,2, 7.74328189,11.0585526, 0.9,-9.9
, a4 S. d0 [6 M. C# l21, 1,1.5, 4.12975034,-5.89789472, 0.75,-8.254 u/ X1 H Y2 s
326, 1,1.5, -2.03781207,7.37236840, 0.60,-6.6
. u% K/ A0 c5 Y8 p. W. k8 q& T71.4514, 1.49742233,1.16448394, 5.7305871,-6.9397673, 0.6374019,-7.011421122 c5 X' x7 a) l; D* r
37.5, 0,0, 2.123,2.567, 0,-6.52,0,-6.7,0,-6.625
+ D) k9 J( E1 Y" [8 B( M7.5, 0,0, 3.123,3.567, 0,-3.82,0,-6.37,0,-2.525
9 }& K( _% g5 B b-32.5, -2.23,0, 4.6234,2.678, 0,-2.5,0,-7.8,0,-10.35
4 V" v. c7 s. d- A f/ {& G-42.5, -3.23,0, 3.6234,4.678, 0,-3.25,0,-5.18,0,-7.35
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