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UID396100
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在线时间 小时
注册时间2007-10-17
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发表于 2011-12-24 13:07:17
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来自: 中国山东青岛
工具 宏 打开VBA管理器: m) k5 \/ ^ T' a2 n- i. F" y
插入模块 复制如下 运行 即得渐开线 有了渐开线 齿轮不就出来了吗
3 S, K; Q- j" |+ F& k% aSub jkx()
+ d" D% _; n) V- gRem 绘制渐开线,
6 Z6 }, S2 F6 u9 y( O+ [Dim d As Double '节圆直径- U0 y g9 P3 a/ G" c# Z. R( i
Dim r As Double '节圆半径
; Y' Z, Y* V: |) p, \1 p- uDim A As Double '总展开角度) O* }) ^+ q7 A8 ? Z
Dim Ai As Double '展开角度
5 b; K5 V/ e. h# I. zDim Li As Double '展开弧长5 d! o" H* A& f) a i
d = 1003 Q0 ]. I4 \1 u2 P( o& r3 }
A = 360) r7 S- G! q2 C
r = d / 2$ U2 O# [( p+ o: D, R$ F9 |, ]
Dim Pnt1(2) As Double, |' _+ R8 v' l
Dim Pnt2(2) As Double
. a" o% f/ v; P/ d6 L, O. h5 ADim PntLst() As Double, N As Integer
* {# T" q$ }% }( M: H6 _ H% a" `ThisDrawing.ModelSpace.AddCircle Pnt1, r; p5 v+ c6 \6 M
For Ai = 0 To A * Atn(1) / 45# Step Atn(1) / 45#
" z9 j/ n$ S0 K; }8 `; [+ RLi = r * Ai
" v8 I! D C' b( {6 bPnt1(0) = r * Sin(Ai)
" G2 `8 C4 ~0 H8 L* A# nPnt1(1) = r * Cos(Ai)
! |* V! A0 C; J0 f. p) t, C! \5 v& {Pnt2(0) = Pnt1(0) - Li * Cos(-Ai)
0 u; Z7 _0 X! F4 j4 J- [& ~) I! pPnt2(1) = Pnt1(1) - Li * Sin(-Ai)6 _) B- H# D3 I) v ^# C
ThisDrawing.ModelSpace.AddLine Pnt1, Pnt2
7 G* k" ~ ^% LN = N + 1. R( {9 w) e! o3 x G
ReDim Preserve PntLst(N * 2 - 1)$ a5 O: S* b9 p
PntLst(N * 2 - 2) = Pnt2(0)
; T7 g9 G+ h" k* {PntLst(N * 2 - 1) = Pnt2(1) A$ G4 w0 m2 ~, W/ z. K9 p
Next0 v9 c8 @0 {& y( ^8 r/ Y0 j
If N > 1 Then
: S. Q: ` L2 V+ n9 @ |ThisDrawing.ModelSpace.AddLightWeightPolyline PntLst/ U4 m9 J- W/ s( Z" ~9 D3 X
End If6 G& d6 E3 t: l O- P1 W
End Sub |
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