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UID396100
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在线时间 小时
注册时间2007-10-17
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发表于 2011-12-24 13:07:17
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来自: 中国山东青岛
工具 宏 打开VBA管理器$ y _9 T9 C5 D3 S6 C
插入模块 复制如下 运行 即得渐开线 有了渐开线 齿轮不就出来了吗/ t' `: P' K( ~9 ^$ X
Sub jkx()* `6 q; J, J3 M0 n5 g# _% q
Rem 绘制渐开线,
: @2 o4 j( k! _Dim d As Double '节圆直径
: U3 H! Y' p0 P8 I" x$ FDim r As Double '节圆半径* ^, d7 C" N8 y0 r
Dim A As Double '总展开角度
1 H9 R6 ^( |, w h0 _5 ]! |Dim Ai As Double '展开角度2 e9 L0 A$ r* D
Dim Li As Double '展开弧长
2 b5 [* d. D7 C& `7 ]d = 100
* E" a# m" c/ [* \7 ~1 gA = 360
. |8 o: o3 j/ s$ p# W% a1 Dr = d / 2
: k7 g$ k8 ~8 y. r0 hDim Pnt1(2) As Double' o2 u3 n/ p8 H& J2 j$ l1 e( m
Dim Pnt2(2) As Double4 d ^0 `! l; c% m- Q! ^
Dim PntLst() As Double, N As Integer. G; X7 U# ~! v' D7 |
ThisDrawing.ModelSpace.AddCircle Pnt1, r
3 a# w+ K5 E; _( `5 U" CFor Ai = 0 To A * Atn(1) / 45# Step Atn(1) / 45#- U6 C* K6 Z- C' a* P! O; @6 L
Li = r * Ai' `+ N+ }+ h b
Pnt1(0) = r * Sin(Ai)
" w8 N e& i, E6 W* yPnt1(1) = r * Cos(Ai). d/ H, j7 A9 T. u$ U6 i
Pnt2(0) = Pnt1(0) - Li * Cos(-Ai)2 f4 E G3 F, a3 p3 O4 e1 m/ |1 [% h! z I
Pnt2(1) = Pnt1(1) - Li * Sin(-Ai)
* V d% B) ]+ Z/ EThisDrawing.ModelSpace.AddLine Pnt1, Pnt2
7 F) y* r# i( e# `1 HN = N + 1 O0 i- j; O S! @2 b
ReDim Preserve PntLst(N * 2 - 1)
% z( p' r! t$ b; ~+ |, n% ?5 sPntLst(N * 2 - 2) = Pnt2(0)
% f, S/ x' a+ U& {2 o! s3 GPntLst(N * 2 - 1) = Pnt2(1)
* \7 D. }; q8 [Next
0 g3 u F( y1 ?. o& }9 @" sIf N > 1 Then; G* Q. z/ ^" M6 \6 J
ThisDrawing.ModelSpace.AddLightWeightPolyline PntLst4 ~0 x4 | b% i/ h. u3 O. T3 `
End If
! A& N& f& D+ o* W" lEnd Sub |
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