|
|
马上注册,结识高手,享用更多资源,轻松玩转三维网社区。
您需要 登录 才可以下载或查看,没有帐号?注册
x
本帖最后由 woaishuijia 于 2011-7-21 05:43 编辑
( z8 e1 f6 p% e [3 t) c3 h, x. D3 t: n4 \
用VBa做了个简单的小程序,居然提示“无效的过程调用或参数”
' B8 ? |. f; V' ]程序:4 e" H8 u9 U$ d/ }6 T
- Public Sub HTT()/ B s) S% Q; {/ j" n, `
- Dim Pt0, PT00 As Variant& G: \( J& p. p0 g7 d
- Dim PT1(0 To 2), PT2(0 To 2), PT3(0 To 2) As Double
+ ? f6 a% g( l7 h4 Y - Dim L0, L1 As Double
! p4 o3 O5 r4 Q1 I1 S7 F: E3 d - Dim i, m, n As Integer- s2 I2 H- W7 Y% X+ ^
- Dim ALine As AcadLine
! Z8 W2 D. M/ k; w( p0 W - Pt0 = ThisDrawing.Utility.GetPoint(, "基点:")
; z5 q7 ]8 Q( V6 e7 M - X1 = Pt0(0)
+ R" f6 H" L2 B% a' e- |8 W - Y1 = Pt0(1)
2 f1 K2 V% M$ V! j& p - L0 = ThisDrawing.Utility.GetDistance(, "单节筒节宽度:")9 e+ g5 x V* k# j
- L1 = ThisDrawing.Utility.GetDistance(, "筒节直径:")3 [! j9 v5 T4 U$ W; T) ~
- PT1(0) = Pt0(0) + L1+ J# s2 R9 y* e. a, ?. A) q
- PT1(1) = Pt0(1)9 r$ d6 L& z3 j e( @
- PT1(2) = Pt0(2)( K& O: P$ j7 L" l( s, g0 z
- PT2(0) = Pt0(0) + L1* Y- r1 D1 W! R5 Z
- PT2(1) = Pt0(1) - l2+ t# n6 i' Q$ ?( \' U
- PT2(2) = Pt0(2)
& C7 f9 F" x5 w9 @3 ?3 [+ o& k$ m - PT3(0) = Pt0(0): c8 e- ]9 D8 j
- PT3(1) = Pt0(1) - l2
+ Q/ \! O* x. f - PT3(2) = Pt0(2)8 t+ O4 O9 E+ f$ z9 K9 S6 c
- 8 K9 c9 L1 E& e! m) L7 [9 f7 j4 _
- Set ALine = ThisDrawing.ModelSpace.AddLine(Pt0, PT1)' n- e& F$ t1 V1 `1 `5 l, ]" y
- Set ALine = ThisDrawing.ModelSpace.AddLine(PT1, PT2)) J w# H5 Y$ f
- Set ALine = ThisDrawing.ModelSpace.AddLine(PT2, PT3)
8 V) @) w4 u/ I4 d; y - Set ALine = ThisDrawing.ModelSpace.AddLine(PT3, Pt0)
# x# ^0 k6 h8 I) P/ @/ {* C - ZoomAll
( m! I( E# `6 {* @4 A) w - End Sub
复制代码 % Y. n7 S8 Y1 |
错误提示:
' q% @1 y* O' _7 i8 g& G
, O3 |7 v7 n/ d! u7 {0 i2 g( c
有知道如何解决的吗? |
|