关于UG/OPEN API的问题

sencewm

依然是菜鸟求助
. Y* a, X( h) F0 h. }, R我用UIStyler建立了一个按钮，那如何实现：点击该按钮后可以用鼠标选择一曲线，获得该曲线中点坐标位置，我的程序如下，但是似乎总是死循环。
int GP_action_0_act_cb ( int dialog_id,
- ^7 E# o& T' ~/ H( r) G             void * client_data,
             UF_STYLER_item_value_type_p_t callback_data)
{
     /* Make sure User Function is available. */  
8 m; a+ H1 I6 k/ v2 W7 Q     if ( UF_initialize() != 0)
$ B+ w4 Q) ^2 D  [9 M6 v+ I$ m          return ( UF_UI_CB_CONTINUE_DIALOG );
2 o- l3 q* ?6 m5 [2 J7 l     /* ---- Enter your callback code here ----- */
char message[133];
& L4 ~. ^# B$ f  g8 o) x# vmessage[0]='\0';
  @& E) b6 K  K: E2 b- ]& V1 e6 s6 istrcpy(message, "请选择一条曲线");
UF_UI_selection_options_t opts;
UF_UI_mask_t mask;
& g2 ^( Y( Y( H# ], D8 g2 e( hint response;
6 d) p9 H- v3 N3 Ztag_t object, view;
3 _9 `8 j* V8 S+ F( Mdouble cursor[3];
int unhighlight=0;
5 y+ v4 g3 A8 c. z1 `+ n
' L+ N! X9 L" m$ a' \3 m. ZUF_initialize();
8 \6 \) g$ Z1 q7 ~. c4 [opts.other_options=0;
9 {' K+ F6 ]7 V% c  V( p, Oopts.reserved=NULL;
opts.num_mask_triples=1;
: R  S3 c& i7 L. U- {( B8 m2 Vopts.mask_triples=&mask;
) z$ e) F8 Q1 S" C. p( H$ J* u2 @opts.mask_triples->object_type=UF_spline_type;
opts.mask_triples->object_subtype=0;
opts.mask_triples->solid_type=0;
opts.scope=UF_UI_SEL_SCOPE_ANY_IN_ASSEMBLY;
double port[3];
6 P: a! x/ W7 A! ^! k2 _
) ?2 m: Z4 f8 ddo{int irc=UF_UI_select_single(message, &opts, &response, &object, cursor, &view);}
6 s( b, L* W1 ]. T4 ]9 @5 twhile (!(response==UF_UI_OBJECT_SELECTED));
& {; w4 ?5 S4 v' t! f6 w( Oif (response!=UF_UI_OBJECT_SELECTED)
{
uc1601("No Curve Selected",1);
1 s6 J( a2 u7 T- jUF_terminate ();
return (UF_UI_CB_CONTINUE_DIALOG);
4 I, o+ |1 p5 Q$ M5 v}
  
int ret=UF_MODL_ask_curve_props(object,0.5,port,NULL,NULL,NULL,NULL,NULL);
4 T* m  @) X7 v) r  B  char message2[133];
  message2[0]='\0';
  sprintf (message2, "曲线中点坐标为：%f,%f,%f",port[0],port[1],port[2]);
  uc1601(message2,1);
. [) k; [1 F/ D
* S/ o( M" O# r, Z$ W% QUF_terminate ();
return (UF_UI_CB_CONTINUE_DIALOG);
3 O  P/ v3 `1 t% N& i   }

yby303

我赛,怎么是这种呀
! c1 U3 H' _: c, p, x折是参数花的设计吗,