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发表于 2007-5-14 20:47:38
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来自: 中国湖北武汉
也被这个问题难住过,现在解决了,仅9版本
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; P4 Y6 S4 A4 `& Z加入这些可以做到加工余量信息0 E `4 I$ D9 @- |( R( y' X
# --------------------------------------------------------------------------7 E. L/ x) H0 j' _- s/ c
# Common User-defined Variable Initializations (not switches!)7 U. V7 _; ~* T0 |
# --------------------------------------------------------------------------
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#XYZ stock variables
# b" g8 k8 M) @xy_stock : 0 #Declare a unmeric variable to hold4 C7 ` Q: L+ U" @
#the "XY stock to leave" setting
+ U& b& F6 P. O6 z% a9 az_stock : 0 #Declare a unmeric variable to hold
3 g8 L" x8 S% Y# c; c! H N #the "Z stock to leave" setting
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& ~3 D( X6 [ sfmt "TOOL = " 4 tnote # Note format7 h" s$ y) W8 T5 f! X
fmt "DIA. OFF. - " 4 toffnote # Note format
* D9 w% q3 K+ ~0 l* z% z0 v afmt "LENGTH - " 4 tlngnote # Note format
, \" a6 [5 l- Y1 m4 ?1 @( t& }fmt "DIA. = " 2 tldia # Note format
- n. ` n: t7 M% N- N0 r/ E& a ^fmt " RAD. = " 2 tcr # Note format1 i: r1 h9 n" h/ W
fmt "XY= " 2 xy_stock # Assign an output format 5 M3 S& A. I- v2 Y9 w8 `9 A! N
fmt "Z = " 2 z_stock # Assign an output format) ]1 S5 ~- x7 p3 s
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# [; p9 a5 ?% l% c7 B7 X"(STOCK:",*xy_stock," ",*z_stock,")"5 X# }, E: Q( U1 a* t& E2 B0 ^9 f
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-------------------------------------------------------------------------- T7 t$ o* L6 J5 k6 x, s0 m% _# a/ }
# XYZ Stock setting
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pparameter #Information from parameter
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#Capture parameter values' X/ {) r$ P) E% S0 H- S+ c/ |
if prmcode =10010, xy_stock = rpar(sparameter, 1)$ f+ ^* L* t! m4 i3 i
if prmcode =10068, z_stock = rpar(sparameter, 1)
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这里如下设置 R# m* ~/ F6 l" f' b( J' O
1501. Insert parameter information in the ascii NCI? y4 H( o7 G1 s a3 Y. Z: X- d
1502. Write operation information to binary file (.ops)? y" K! K0 a/ e: w7 u; w
1503. Write transform operations (0=transform ops, 1=source ops, 2=both)? 1
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这样的值才不为零 |
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