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发表于 2012-3-17 11:54:40
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来自： 中国台湾
本帖最后由 norno 于 2012-3-17 12:00 编辑
7 @9 K( T, K: ] t; v5 `1 h+ J% s' _" S5 u/ [* Z
用筆記本打開後處理程式) p: E1 t$ K. c0 z* r4 L
3 _) _! {+ U$ t" l3 z4 \7 e. d搜尋這一行看看有沒有這一行==> fmt "F" 15 feed #Feedrate; N+ [' d, {* F5 h/ [' b
如果跟上面一樣0 a0 a$ C# R1 U% b6 K9 x- m
就把下面紅色那一行改成後面藍色的試試吧。
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) x# j0 j2 I! E2 l$ o! V$ f/ t$ v# --------------------------------------------------------------------------9 T$ `" Z" ~" T d. F! F1 k
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# Format statements - n=nonmodal, l=leading, t=trailing, i=inc, d=delta
& a4 T V( Q. {# ?# --------------------------------------------------------------------------' [) w. r; m) R$ V) F
#Default english/metric position format statements
: M6 C+ Y1 r5 Tfs2 1 0.7 0.6 #Decimal, absolute, 7 place, default for initialize ( 2 s5 H# }* ]' S; S; Q5 a( n
fs2 2 0.4 0.3 #Decimal, absolute, 4/3 place1 }1 L, u; U/ n7 x
fs2 3 0.4 0.3d #Decimal, delta, 4/3 place
4 v3 K1 ?+ y. N$ |#Common format statements
3 c6 G* o7 e; W) F: {( Z7 W' Afs2 4 1 0 1 0 #Integer, not leading4 i& C: J% V7 Q
fs2 5 2 0 2 0l #Integer, force two leading
- W8 ?9 t4 B( x- ? }( L" Tfs2 6 3 0 3 0l #Integer, force three leading$ S; N" V- G# H, b+ A
fs2 7 4 0 4 0l #Integer, force four leading
) q5 V5 @, o) {fs2 9 0.1 0.1 #Decimal, absolute, 1 place
" B4 [: {: h! k1 U% ~fs2 10 0.2 0.2 #Decimal, absolute, 2 place
5 k( s" m1 F, a% bfs2 11 0.3 0.3 #Decimal, absolute, 3 place3 L/ Z+ E% O: J" ]) i: B
fs2 12 0.4 0.4 #Decimal, absolute, 4 place: ~! W% W! _ i4 m+ K
fs2 13 0.5 0.5 #Decimal, absolute, 5 place
2 _- @) y& Y4 i$ `" a' y8 sfs2 14 0.3 0.3d #Decimal, delta, 3 place
2 f/ W: _& }% S) ~! p' Zfs2 15 0.2 0.1 #Decimal, absolute, 2/1 place (feedrate) ==> fs2 15 0.2 1.1l #Decimal, absolute, 2/1 place (feedrate)& I: m! ]4 J, b* r
fs2 16 1 0 1 0n #Integer, forced output" R: Y% v4 {- N% {: r4 }
fs2 17 0.2 0.3 #Decimal, absolute, 2/3 place (tapping feedrate)3 B/ G1 h6 y# _
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