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本帖最后由 woaishuijia 于 2011-7-21 05:43 编辑
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, z) R, |; A3 ~+ P# F用VBa做了个简单的小程序,居然提示“无效的过程调用或参数”. K& d: i8 k$ |& D9 ^, O$ t
程序:+ ?1 Q4 y4 M( F3 t3 }! M
- Public Sub HTT()! I, i6 j; r" O2 Y* V/ }4 W
- Dim Pt0, PT00 As Variant
. w ~/ _- A7 b9 R2 M% H3 Y7 U - Dim PT1(0 To 2), PT2(0 To 2), PT3(0 To 2) As Double
9 u# }; J& J- m1 E* v - Dim L0, L1 As Double
$ a: C' A3 m# E3 \+ u9 K - Dim i, m, n As Integer
5 Z* j) ~5 u8 W7 i3 { - Dim ALine As AcadLine
5 s' N/ {+ o8 S0 k% O, a - Pt0 = ThisDrawing.Utility.GetPoint(, "基点:")
8 I$ E, U7 r* n! }: T - X1 = Pt0(0)
# S1 g* Y' r+ R& A! ^' b( C - Y1 = Pt0(1)
F' C) o5 [! c1 @0 x% t3 H1 y' u - L0 = ThisDrawing.Utility.GetDistance(, "单节筒节宽度:")
3 F* a. t1 a7 a5 A; m& W5 B - L1 = ThisDrawing.Utility.GetDistance(, "筒节直径:")+ l3 w5 L. s/ |. F L8 b
- PT1(0) = Pt0(0) + L1
' h& h. a7 _3 h! k' l( o- y# q - PT1(1) = Pt0(1)
0 w3 x8 ^) d9 e5 P7 [9 f - PT1(2) = Pt0(2)
* I% Q+ D9 x; S4 O) J - PT2(0) = Pt0(0) + L12 B; ~2 h! t1 E$ m% A/ _
- PT2(1) = Pt0(1) - l2+ d: L h- X( e8 \0 Z3 D% j7 M$ j/ W0 H
- PT2(2) = Pt0(2)
& l4 O) S/ ]! {. I - PT3(0) = Pt0(0)
: Q% A% s% m* A* I1 Y( w- H - PT3(1) = Pt0(1) - l2
5 l. z, g7 l* s/ m+ {% A$ j - PT3(2) = Pt0(2)( ]( g) `4 J9 V0 {0 g
+ l- G# a# ~+ R; r( x- U2 p! ]- Set ALine = ThisDrawing.ModelSpace.AddLine(Pt0, PT1)/ U. s4 |( i7 q. w) x
- Set ALine = ThisDrawing.ModelSpace.AddLine(PT1, PT2)& z+ ]- a9 S3 M* d. V( T& P
- Set ALine = ThisDrawing.ModelSpace.AddLine(PT2, PT3)
. |, X0 I {. h1 S$ h8 |$ W; f - Set ALine = ThisDrawing.ModelSpace.AddLine(PT3, Pt0)
8 g* F8 |- l8 b3 W, b s& Y4 ? - ZoomAll/ I* Y8 h9 M- W E5 ^; }9 `# K
- End Sub
复制代码
; R: O) Q2 B- y) e错误提示:+ k9 c+ o7 R/ b+ N2 D' L" P
+ Z5 j& c+ B5 K/ X, P有知道如何解决的吗? |
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