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发表于 2008-3-12 13:52:33
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来自: 中国广东深圳
我给你一个线割完整的程式,你认真看看,好好体会一下,他是一个边长为25毫米的方空加工程式
) C+ z; d5 p2 C B( n* N) j# D( = ON OFF IP HRP MAO SV V SF C PIK CTRL WK WT WS WP);
1 f( }- |& t+ A) wC000 = 006 014 2215 000 240 040 8 0050 0 000 0000 020 120 130 045;5 E3 a7 N2 w, y. x0 d. i
C001 = 008 014 2215 000 242 015 8 0050 0 000 0000 020 120 130 055;( u. T' { i4 p! j. a' M ^# F
C002 = 002 023 2215 000 750 048 8 6035 0 000 0000 020 120 130 012;1 ?) t4 ?2 n' ~% X% |5 \/ f
C900 = 000 001 1015 000 000 030 7 7050 0 008 0000 020 120 130 012;" @3 E- j- N/ m9 m E' P+ T4 M
H000 = +000000.010 ;. ]# @# S y$ ?+ j* Q3 `) z
H001 = +000000.192 ;) R4 ~7 E( C& m; i: F7 \
H002 = +000000.127 ;" k6 [* v# p/ i f" R1 Z/ C) ^
H003 = +000000.107 ;7 t) \% D/ j% Z0 q
( FIG-1 1ST REMAINS);
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T84;* l# T# v9 k, I7 v. _
C000;
# { K- w( N% Q+ K" Y- wG51A0G41H000G01X12.571Y25.0;
1 c0 y |7 I7 |7 P9 z0 jA0.02;
5 t( s' A2 H4 o* I( D& |C001H001;
7 J" k% D4 V' B. xM98P0001;
7 \( c: M0 c) FT85;
) `; a3 I% e9 C+ k. G( FIG-1 2ND RECIPROCATE);
9 {3 a, Y! I! C* o& |' ?; d! t& }C002;3 E. Y9 K6 h2 J! h6 l( F
G52A0G42H000G01X11.971Y25.0;
9 ?3 Q4 j; o( b! C3 r7 p- c5 f, t! lA0.02;
! h: N" d$ ~3 y+ O( ]: |8 VH002;+ E3 _( F! P/ g9 q* o1 w+ e' A' V
M98P0002;% w: n5 Y$ l$ O4 f1 ]/ a" |- c
C900;+ _( P5 t1 e6 u% v
G51A0G41H000G01X12.571Y25.0;
# u2 d# p) `; v; @$ hA0.02;! B3 q9 F6 ] {% X& |( I6 {; ~* Y
H003; R) W1 j/ x2 E) x5 f! j6 b$ L* |- [; K
M98P0001;: J7 m" |$ Z. z8 I
( FIG-1 CUT);
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2 Y3 Y: q" V" A" X' R1 vA0.02;
# Q) _2 Y( f3 H3 D E) KH001;
0 C! B0 j4 f* y; l, V- c; h- CM98P0004;
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M02;1 n5 V; C+ A6 y
. | D3 @- w0 Y6 `% L
N0001;
, \+ J& ^$ b2 u+ [1 A* nG01X25.0Y25.0;: N' m) T# V2 p- i( W
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A0.0;
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M99;. M" X! k" x2 v, F4 w# Z2 U' P
; q: |: W! H. L/ w2 }1 p0 AN0002;
" c# G" j' x- E% D! jG01X0.0Y25.0;& \' @8 B: y8 j' A) Z+ r8 l8 j( }
A0.02;
8 M# d* K& g' c. M$ aY0.0;& Y, t, z8 Z& Q ]( \
X25.0;& U1 H( J, x; y- [! v& ^: N
Y25.0;; T$ b( Y. k# a3 A# F% L5 l& o# A
X12.571;
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G50G40H000Y11.884;. M3 u" F7 k: B
M99;4 ~9 L" I7 X5 L5 H& B
+ W. ^, ~- j9 S1 ?
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