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发表于 2008-3-12 13:52:33
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来自： 中国广东深圳
我给你一个线割完整的程式,你认真看看,好好体会一下,他是一个边长为25毫米的方空加工程式 p1 a) C" A# \- r
( = ON OFF IP HRP MAO SV V SF C PIK CTRL WK WT WS WP);
" v2 W; K" l: _5 c$ a# N# I- `9 D) TC000 = 006 014 2215 000 240 040 8 0050 0 000 0000 020 120 130 045; g3 q; ~4 m, y6 q9 B- y
C001 = 008 014 2215 000 242 015 8 0050 0 000 0000 020 120 130 055;
# I7 y k" N% j6 L+ ]4 V% IC002 = 002 023 2215 000 750 048 8 6035 0 000 0000 020 120 130 012;
4 t9 x! T6 d5 r8 _6 a5 |: vC900 = 000 001 1015 000 000 030 7 7050 0 008 0000 020 120 130 012;
4 ~& C! f; J8 e! d# c) _0 WH000 = +000000.010 ;' W* ~# x2 a3 U; g+ R* W. K* b
H001 = +000000.192 ;7 \& }, K7 I4 K1 v3 D7 v
H002 = +000000.127 ;
( _3 Y6 l" @0 H5 X! jH003 = +000000.107 ;0 U( u/ [' M9 Z& C+ v8 x
( FIG-1 1ST REMAINS);
Q; W1 @! x9 C3 C) K! fQAIC(2,1,0.1000,003.0,0.1300,0.0400,016.0,0008,0028,10,035);4 |* X( c/ Y: T; u! S
TP35.0;
1 `% t7 @/ U: i/ G yTN0.0;6 M, P! A) @5 w# W/ R& E8 D& l
G54;6 ?5 d+ ?. V9 i2 Q0 l
G90;
) ]+ t# ]' b# T0 ]" k! |' KG92X12.571Y11.884Z0;
& q' c2 c6 y1 c0 B- a/ c- }G29;
7 ^8 |" V( B( c: `4 U% nT94;/ n1 n2 }9 G4 b V7 ]
T84;
4 c' f) i5 z) U, u# OC000;& L& \! u0 L6 O) l" m) C
G51A0G41H000G01X12.571Y25.0;
! m; N E5 I0 V" v( b2 z, \2 ~A0.02;! C! u( { U1 Q: E s
C001H001;$ V6 h3 s+ k. u S* `6 J
M98P0001;- \- f; ^. }1 ` w: h+ _, {
T85;
- x6 G* ^2 n$ P% C( FIG-1 2ND RECIPROCATE);" b# {, \: l# W8 ` `+ v
C002;( |/ |7 C7 O; U5 f ?
G52A0G42H000G01X11.971Y25.0;$ U3 o ~" z, |# Y/ ~$ \! `
A0.02;" r3 j" T& ?/ _! P' A2 Z. C1 {
H002;
S8 [8 H |* hM98P0002;3 U! |' u7 p1 G$ \# i
C900;
9 i' }( n% ]6 _6 z/ t$ d9 h9 kG51A0G41H000G01X12.571Y25.0;
% F5 f3 @7 U% yA0.02;
$ e0 @7 e1 j# `, j4 DH003;
, B; r7 }; @1 d& [) qM98P0001;( W2 H1 @& _) V0 z: _, k
( FIG-1 CUT);
8 P7 H. F# z* y0 A' b9 F9 B# R" @M01;- @$ t, \/ d- K1 W0 Q: r
T90;
3 |( d2 O4 x6 ^3 J. m" [$ ~G00X12.571Y11.884;* r5 {- K7 u) g1 a' l( j7 B
T91;
( \3 p+ v3 X' I" OT84;
. P2 ]( V3 j6 u; aC001;. o+ a8 n( y' ^4 t( ^
G52A0G42H000G01X12.571Y25.0;
/ K& z" U; |3 w* J7 \A0.02;
5 \% e) w E5 i5 i9 B; fH001;
Y- G* t, q1 K6 L) ^M98P0004;
) }. s* M6 T( _! K- I0 L; yT85;$ s1 a5 N* w! k4 J4 S
M02;
) p, T5 c: x" o7 O* m! D! Y% O0 s8 f! ~8 p
N0001;7 E/ J7 S: d* }
G01X25.0Y25.0;
! o% {; k; z* lA0.02;1 b# P6 S4 e2 E+ t- v2 {# W; [- K
Y0.0;
d9 _0 s9 \9 V# ZX0.0;
" e+ _6 S' t" n3 cY25.0;
9 G$ N, c& J3 X+ W; J; c+ IX11.971;
# t( F/ d6 T. y4 J2 s7 G4 ^A0.0;- n3 g+ N" {0 r9 l7 B
G50G40H000Y24.0; z# y# ?9 L* }# j6 ?
M99;2 Y; f' F3 |. c! C t1 D1 Y
u% J+ ^% d. R. D$ R6 QN0002;
& Y" t6 e2 j$ T g7 k. i6 }" vG01X0.0Y25.0;1 f0 t4 k% }) _9 e: S0 X. H
A0.02;
0 T2 D; R- x: h1 \) B$ dY0.0;
' H* `) F8 `8 A' h6 o' Z- V+ rX25.0;1 K$ f! R3 S. z1 b2 |
Y25.0;* `; X1 I0 N7 x' N. w+ Y( r8 {
X12.571;+ @8 R1 |$ F3 e& }" ?0 E
A0.0;+ I# s( j% q0 C. d5 D* H! y
G50G40H000Y11.884;
( e$ f* {7 F" p3 FM99;
4 B0 {" K; U5 V" }0 a6 Y& }2 [8 _4 R0 E( y, b9 }2 ]! M
N0004;
. c& Z p) g- b7 g% J0 Y+ bG01X11.971Y25.0;& F; R/ J6 `% V. n& f
A0.0;$ _4 x7 g3 b& \" [; {& v# ~
M00;, a2 C' S( X0 v7 K
G50G40H000Y24.0;
2 W, K" c5 ]: V2 D$ p$ xM99; |
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