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发表于 2007-5-14 20:47:38
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来自: 中国湖北武汉
也被这个问题难住过,现在解决了,仅9版本# }' j8 G" S( e# ?
4 L$ z) a6 x9 f, n加入这些可以做到加工余量信息
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( j x' f1 A8 l/ b- F4 N; i# Common User-defined Variable Initializations (not switches!)
8 Y# t5 L! K& t/ d: X7 M q# ?' |2 t# --------------------------------------------------------------------------
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+ \4 b# [( Z) t V6 a9 `% l. Z#XYZ stock variables
& `5 P; A/ n' m' p A# Bxy_stock : 0 #Declare a unmeric variable to hold- n, f$ {4 c6 B. {7 Z
#the "XY stock to leave" setting. r2 P/ N6 c V: u3 B
z_stock : 0 #Declare a unmeric variable to hold# G0 A# e8 j; p% }
#the "Z stock to leave" setting: l- B; t) T1 T! P
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) M3 C( _/ ]3 b4 Dfmt "TOOL = " 4 tnote # Note format
$ N! e3 C l4 |8 M; q# Q; t$ Tfmt "DIA. OFF. - " 4 toffnote # Note format$ \9 _4 @ l3 e' ]( l
fmt "LENGTH - " 4 tlngnote # Note format
* a! Y8 v+ |8 n. ffmt "DIA. = " 2 tldia # Note format
4 j& N1 c) H4 o7 sfmt " RAD. = " 2 tcr # Note format
) M7 v; W0 m3 H5 {8 z$ m' |% gfmt "XY= " 2 xy_stock # Assign an output format
- w8 \& @ G; t U0 E0 ^fmt "Z = " 2 z_stock # Assign an output format
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"(STOCK:",*xy_stock," ",*z_stock,")"0 e: V# m1 m' ~3 R e- e3 A/ M. D
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--------------------------------------------------------------------------
2 Z2 j) [4 Q, u! z8 Z% b' `" u# XYZ Stock setting, E& o. n; ]" u+ A7 f0 f- q+ ~- h& P9 Q
# --------------------------------------------------------------------------
# }3 B, d1 k& C3 ]pparameter #Information from parameter
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#Capture parameter values
% j: F b! l- [" b; d1 t if prmcode =10010, xy_stock = rpar(sparameter, 1). y0 z/ A# n% p2 ]6 v
if prmcode =10068, z_stock = rpar(sparameter, 1)
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这里如下设置7 V* f; o% I* F* F2 i$ H
1501. Insert parameter information in the ascii NCI? y! c# ]# I; b- D2 C/ I/ h( @# @" b
1502. Write operation information to binary file (.ops)? y) k# d) X2 }+ Z% Z5 {- j" b
1503. Write transform operations (0=transform ops, 1=source ops, 2=both)? 1& ~' U! ~- e, {) [
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3 P5 ?+ J# D: d' g- ~! l. v6 B这样的值才不为零 |
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