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UID396100
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注册时间2007-10-17
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发表于 2011-12-24 13:07:17
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来自: 中国山东青岛
工具 宏 打开VBA管理器
) `, o- a8 ]9 d5 e8 W 插入模块 复制如下 运行 即得渐开线 有了渐开线 齿轮不就出来了吗
2 E" f$ g, C1 b4 d) v$ gSub jkx(). l6 i9 }: _3 s8 j) _! D9 _
Rem 绘制渐开线,
4 _1 D/ ~% }$ M( n" _5 \Dim d As Double '节圆直径$ j& W; k* q' E P+ p. B
Dim r As Double '节圆半径
0 p1 @$ a9 r" l h* S) ^& `3 m! ODim A As Double '总展开角度8 w/ K1 e! l3 {8 @! c+ ]
Dim Ai As Double '展开角度
( L; X( ~: j( n! S* dDim Li As Double '展开弧长* w- H) a6 X& a5 e7 W
d = 100
7 x- {9 C' P7 O; W( {A = 3608 q5 G0 T0 x4 \* [
r = d / 2# {6 [, c, p2 h7 p
Dim Pnt1(2) As Double
' ?) ?1 [& G% l0 z3 w: PDim Pnt2(2) As Double: c0 f' J6 E1 I4 h/ v) R
Dim PntLst() As Double, N As Integer+ ^, @$ J" _3 ]" ~( Z5 O
ThisDrawing.ModelSpace.AddCircle Pnt1, r
, w% u3 p# Q, {5 y& [. c7 P% o$ F8 YFor Ai = 0 To A * Atn(1) / 45# Step Atn(1) / 45#$ ?4 h% X2 f) z
Li = r * Ai
* q$ O9 f& y3 z5 `" f+ y; dPnt1(0) = r * Sin(Ai)
n- L( O2 h/ u3 K7 kPnt1(1) = r * Cos(Ai)* z4 b# t$ O1 L5 @
Pnt2(0) = Pnt1(0) - Li * Cos(-Ai)
1 L: r2 u9 E7 A% H/ ?Pnt2(1) = Pnt1(1) - Li * Sin(-Ai)
: r; f! t) k( M8 \- ?ThisDrawing.ModelSpace.AddLine Pnt1, Pnt23 X# H4 A6 V% D; C }6 n1 B
N = N + 1( H6 ?2 S4 _2 @- A$ ^
ReDim Preserve PntLst(N * 2 - 1)
4 {8 t0 ]% D& }+ cPntLst(N * 2 - 2) = Pnt2(0)
( W5 g. K4 U( z9 f( {5 ZPntLst(N * 2 - 1) = Pnt2(1)1 n! l4 Q$ y2 |# I _* P
Next4 S7 i1 C% w5 z2 D3 E. `* w
If N > 1 Then
$ f- {( z' d* ~4 k. D' GThisDrawing.ModelSpace.AddLightWeightPolyline PntLst
& B. k8 \$ \1 k# F, t) `/ P7 cEnd If. {* e! W3 q% ]. R/ M$ i* N+ L
End Sub |
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