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UID396100
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在线时间 小时
注册时间2007-10-17
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发表于 2011-12-24 13:07:17
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来自: 中国山东青岛
工具 宏 打开VBA管理器
% M$ y2 n! M$ N2 _* ] 插入模块 复制如下 运行 即得渐开线 有了渐开线 齿轮不就出来了吗
; z% j. s, a; }9 M, j. ^Sub jkx()3 H4 Z$ ^/ p" T( R3 t1 F
Rem 绘制渐开线,
. v. F- X+ S% P; f1 w; F* tDim d As Double '节圆直径, ~2 |5 z! i% {
Dim r As Double '节圆半径
" z1 _& ]8 k: |6 K, v" z3 P$ JDim A As Double '总展开角度
1 `/ k- K# j$ y+ mDim Ai As Double '展开角度
% h) f8 U6 y* r* PDim Li As Double '展开弧长( \/ ?. [4 w1 m) Z% @
d = 1007 M1 ~- A+ o8 r* D2 [+ I
A = 360
S5 D$ K' I6 U4 q' U- f5 P9 dr = d / 2( L2 ?8 d+ \5 W9 e- M' c$ M
Dim Pnt1(2) As Double
( H$ n* X3 V9 v% I/ V% k& kDim Pnt2(2) As Double
6 z- x. @4 ~- j) j" aDim PntLst() As Double, N As Integer
$ K. W% e4 h- ^9 s2 m/ DThisDrawing.ModelSpace.AddCircle Pnt1, r4 C$ \* m( v2 ]0 b# B+ ^
For Ai = 0 To A * Atn(1) / 45# Step Atn(1) / 45#% u* ^; {% M1 c/ A
Li = r * Ai
$ A( z8 W: q3 U/ KPnt1(0) = r * Sin(Ai)7 J/ B% i/ m6 s" K" o" g) e
Pnt1(1) = r * Cos(Ai)
5 ^5 b2 V& `7 N L! zPnt2(0) = Pnt1(0) - Li * Cos(-Ai)7 [8 N! N/ H! ]9 O/ P9 Q
Pnt2(1) = Pnt1(1) - Li * Sin(-Ai) |# z( s2 P0 ~# t; ^* |
ThisDrawing.ModelSpace.AddLine Pnt1, Pnt2
( v9 [; T+ y4 K1 A/ F- K3 o R6 oN = N + 16 _# d8 |" R9 d
ReDim Preserve PntLst(N * 2 - 1) w Z8 I; @: j0 d% [. Q" ~
PntLst(N * 2 - 2) = Pnt2(0); m$ y7 P) Y! M# T7 A2 C: a7 ^+ B
PntLst(N * 2 - 1) = Pnt2(1)
" B, f) d* K, U K# c) k) L! M8 cNext
- h& b$ L. p( g! l$ xIf N > 1 Then
6 H) g7 Z7 _+ }# A6 _# N& Z( vThisDrawing.ModelSpace.AddLightWeightPolyline PntLst) u' g' L% }% s4 Q$ B2 j* x" z
End If5 p( z4 [! W9 U# ~# j
End Sub |
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