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楼主 |
发表于 2016-3-11 15:51:37
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来自: 中国浙江嘉兴
0 V3 |3 I* N J |3 ?* F- I5 Z1 f% r至于用宏的方法,那里可以找到相关资料? 之前已分享不少了,若是不能吸收理解,就僅能抄襲無法廣用.) Q7 i$ X, o# _" C
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如下參考# y/ O- C; J8 L' w+ y4 `
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' ******************************************************************************
I* A: L. P4 D" V# D) a' macro recorded on 03/04/16 by scliang, j/ |/ u* ]+ |* v4 d/ Z
' ******************************************************************************# @! \ d+ U- J5 ?* J" L4 K1 B+ S/ m" o
Dim swApp As Object
7 q# F2 A* p8 qDim Part As Object
' u1 A7 `: K2 M- G) [Dim boolstatus As Boolean
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Sub main()
" _# e# e1 [( O. U1 ]Set swApp = Application.SldWorks6 ?. G% B- i7 o: V/ d
Set Part = swApp.ActiveDoc
' y+ N* }. g9 }" |Set myModelView = Part.ActiveView( @" g$ B- m- W$ V, G I
Dim myDimension As Object" t9 u0 k7 F7 e
pi = Atn(1) * 4+ L5 l4 u5 L/ s
Set myDimension = Part.Parameter("D15@草圖1") '對應控制角度
" E# e' @* Q+ W0 K' c. w$ {For i = 0.1 To 90.1 Step 5
5 o3 x' D4 ^4 ]5 w" @8 R7 O4 I2 }A = i * pi / 180
# C4 q0 c9 U- @8 a- f3 [1 JmyDimension.SystemValue = A
+ x7 r% H8 R D& o! `0 r b5 Rboolstatus = Part.EditRebuild3()
& H& [* J. Y3 h2 r! H8 ]# w6 xmyModelView.RotateAboutCenter 0, 0, ]8 A* U) J' \' Y
Next
' u3 k) Y. N( t5 @For i = 85.1 To 0.05 Step -5
9 I% U q, t3 L1 ^7 V! sA = i * pi / 180
" s2 P. u% a- j/ gmyDimension.SystemValue = A8 [( H7 x9 n0 K; n e# z1 a
boolstatus = Part.EditRebuild3()" q+ {& a0 S Z( L) G
myModelView.RotateAboutCenter 0, 0
& |% w- }8 K. ^) n M! |6 zNext
9 G4 Z9 p5 m" Z5 D) tEnd Sub
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Macro1.rar
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