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发表于 2007-3-9 14:41:30
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来自： 中国辽宁营口
用VBA画图方法
VBA源代码：9 n2 M; h7 e& B+ E+ c, X* i
5 r- Y3 t" Z+ nSub A() '本程序以20圆的圆心为坐标原点) j$ b: u$ n2 S9 ]( `# X
Dim Y As Double '左上方小圆圆心纵坐标
2 u+ g% w6 W1 b- K9 ]0 e6 {; D" O Dim Y1 As Double, Y2 As Double, B As Double, B1 As Double '迭代运算中间变量
3 z, T+ z0 z5 c/ q Dim R As Double '小圆半径
9 q+ A* D, }: f5 y Dim O(2) As Double '坐标原点
; V: g5 v5 b9 U Dim O1(2) As Double '左上方小圆圆心
8 A% y' I9 Z1 A' x* ~$ S Dim O2(2) As Double '右上方小圆圆心
& S, R5 V# b2 A1 h7 ?$ d Dim O3(2) As Double '右下方小圆圆心 e b6 f1 \" G U3 I$ ]+ p5 ?
Dim P1(2) As Double, P2(2) As Double, P3(2) As Double '直线起端点
& d$ M8 w/ Z0 v3 X; b) ?0 U Y1 = 10 '迭代运算边界条件8 f4 X' l3 R0 D7 ~* a. @
Y2 = 20. ^8 _2 P; t3 p% H. ^. Z* l1 c
Do '计算合适的小圆圆心纵坐标& l( X3 m5 _- W4 z- T1 J7 |+ ] K
Y = (Y1 + Y2) / 2
& \& y2 L% ` g B = -(2 + Sqr(2)) * Y ^ 4 - 40 * Sqr(2) * Y ^ 3 + 1600 * Y ^ 2 - 16000 * Sqr(2) * Y + 320000 + 160000 * Sqr(2)
& U; u3 a& e: A6 G If B = 0 Then
" k! I, Z! p& \) F. n( D% U9 h1 @4 G Exit Do
, N5 O" w+ _) n. a% ^$ m3 w+ `' v ElseIf Y = Y1 Then6 O' i3 d. ?1 ]& C1 `$ z
B1 = -(2 + Sqr(2)) * Y2 ^ 4 - 40 * Sqr(2) * Y2 ^ 3 + 1600 * Y2 ^ 2 - 16000 * Sqr(2) * Y2 + 320000 + 160000 * Sqr(2)
/ g8 e; Q+ q2 }' z4 z If Abs(B1) < Abs(B) Then Y = Y2" ^5 ~+ b7 d1 n! B9 v/ f
Exit Do
4 n, A3 i: d) P; T) |. M b ElseIf Y = Y2 Then! W- O( o/ D5 z$ X, C
B1 = -(2 + Sqr(2)) * Y1 ^ 4 - 40 * Sqr(2) * Y1 ^ 3 + 1600 * Y1 ^ 2 - 16000 * Sqr(2) * Y1 + 320000 + 160000 * Sqr(2)! E1 Z3 h t; q& h! C0 Y
If Abs(B1) < Abs(B) Then Y = Y1
* h* ^8 M4 W7 J Exit Do! x7 D _3 L, ~% z4 n C
ElseIf B > 0 Then/ z! F9 P$ m2 Y2 C9 D: q' ~
Y1 = Y
9 d/ k9 @4 ^, _" o( g! h$ W I Else$ B$ O" y+ g. J4 d" r" e
Y2 = Y" s: E p6 i" S/ U* I$ b& A5 T$ Z
End If
# w+ Z% z+ W A% x { Loop
7 V5 \) w) W+ w( P R = Y ^ 2 / 40 '小圆半径
V% j( ?- @2 h4 Q) v O1(0) = R - 10; B6 ]8 S" p3 F0 F+ @3 J
O1(1) = Y '各点赋值5 s4 f# R* r( P r# \7 J
O2(0) = Sqr(0.5) * (10 + R)
; |0 D% E* ~* k O2(1) = O2(0)1 K6 k$ p' m! ^8 @! X# }
O3(0) = O1(1)
o& X8 c2 W9 r% P% w( r O3(1) = O1(0)
+ |( Y. N$ ?% y- g1 M; Z P1(0) = -10 _2 b2 R) j+ H6 ~3 G
P1(1) = -10+ z( G" l8 K' U3 A6 b/ j8 \
P2(0) = -102 h0 ?. ?# h8 W+ f0 j1 k0 m
P2(1) = 20
8 C) B2 ~- C( ^4 O, j2 Q P3(0) = 20
: t& [3 {0 J; Q0 J3 b P3(1) = -10
# H; ]; P4 ~* o8 V1 ? With ThisDrawing) A4 [2 P3 K+ d+ U7 I; P
.ModelSpace.AddLine P1, P2 '画直线
) J. \+ a! _9 F6 U .ModelSpace.AddLine P1, P3
. M: H6 T9 D t .ModelSpace.AddCircle O, 10 '画大圆
B+ L* k H# a .ModelSpace.AddCircle O1, R '画三个小圆% A$ t/ F! o6 I, k, E( q& s& M
.ModelSpace.AddCircle O2, R
2 |5 p4 L) t! b/ T .ModelSpace.AddCircle O3, R6 @: g. g3 m- ?* ?2 b
End With5 ~" Y2 @8 O% }- i$ v
End Sub |
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发表于 2007-3-9 09:43:24
发表于 2007-3-9 12:21:41
楼主
都好厉害，我没想到的都给想到了／
:L