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发表于 2007-5-14 20:47:38
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来自： 中国湖北武汉
也被这个问题难住过，现在解决了，仅9版本
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! S0 z0 i) t2 U9 x7 z5 x加入这些可以做到加工余量信息4 m5 n( _+ M& N" ~& F _
# --------------------------------------------------------------------------$ t9 Z1 P$ {7 C* Y- ?$ n
# Common User-defined Variable Initializations (not switches!)
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#XYZ stock variables
8 M& X$ D! @& g0 q1 @7 Pxy_stock : 0 #Declare a unmeric variable to hold) I# P# J; O7 I& l# n4 ^) N- J
#the "XY stock to leave" setting0 W. P3 \) ~7 k F* Y
z_stock : 0 #Declare a unmeric variable to hold5 V2 `7 g# W6 z4 }
#the "Z stock to leave" setting
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! s" M2 I6 P% u5 Q0 V8 o$ k+ `fmt "TOOL = " 4 tnote # Note format
4 _7 a, u/ w! Y. V/ U6 Cfmt "DIA. OFF. - " 4 toffnote # Note format
3 ~, \0 g7 [8 E" Z: {- m6 ^/ ^0 xfmt "LENGTH - " 4 tlngnote # Note format
0 ~- S4 J. H0 t; l3 bfmt "DIA. = " 2 tldia # Note format2 e2 ?4 c0 R. q: [
fmt " RAD. = " 2 tcr # Note format7 t; f5 E5 G" [$ l4 ` L
fmt "XY= " 2 xy_stock # Assign an output format 1 f. j M7 o: f' D& M
fmt "Z = " 2 z_stock # Assign an output format% W1 K6 }- z3 C2 B
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$ l, t s. e2 M! o3 w"(STOCK:",*xy_stock," ",*z_stock,")"4 o- n0 Q4 n. @3 a6 f( D4 o9 V; N! t
2 @. v. p9 w1 o4 f% f, p--------------------------------------------------------------------------- |6 @0 n/ r5 _0 s1 ?: Y
# XYZ Stock setting2 F7 I7 X! U6 B" f+ p
# --------------------------------------------------------------------------
0 [: s9 L3 D( i8 I9 W3 ]pparameter #Information from parameter: ?+ d0 K" p8 O9 w2 V# q
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#Capture parameter values
. Z! ?# x. W% a& q9 i# Z9 Y if prmcode =10010, xy_stock = rpar(sparameter, 1)- r6 o2 |& ?) w* @7 c) k
if prmcode =10068, z_stock = rpar(sparameter, 1)
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这里如下设置4 r% b! u9 V, O9 I7 \1 _9 y1 a/ ]
1501. Insert parameter information in the ascii NCI? y- {5 \5 E' k* P) e- |9 l+ w2 w! C
1502. Write operation information to binary file (.ops)? y
0 d7 S6 I) v2 R1 E1503. Write transform operations (0=transform ops, 1=source ops, 2=both)? 1/ y' J7 y: `" @, [. B& E
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' b- [" _& E) M& V8 m这样的值才不为零 |
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