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楼主 |
发表于 2016-3-11 15:51:37
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来自： 中国浙江嘉兴
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至于用宏的方法，那里可以找到相关资料？ 之前已分享不少了,若是不能吸收理解,就僅能抄襲無法廣用.; S- x) H/ i3 G# R0 r [/ T
# T+ p5 U9 }4 k/ T如下參考
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& p9 N8 d' P: @7 {+ j. v0 S8 L' ******************************************************************************6 v4 \+ X J5 P5 I( q- G+ f
' macro recorded on 03/04/16 by scliang
! @( [( k* g, T0 j# @/ W' ******************************************************************************
" k- k5 F2 {7 L/ h9 N8 VDim swApp As Object$ Y" s4 M7 Q8 a
Dim Part As Object
7 S- R% ]* m( y8 D0 jDim boolstatus As Boolean
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Sub main()8 M. q7 ?' n. P1 ]9 S5 r6 u' K
Set swApp = Application.SldWorks
0 Q% Z0 M8 j$ h! jSet Part = swApp.ActiveDoc
% T# d" j; B/ z: q- G7 TSet myModelView = Part.ActiveView
6 v6 l2 d5 i% V7 CDim myDimension As Object
, x8 w6 o* o0 s+ V7 hpi = Atn(1) * 4
( A/ x( r* }% OSet myDimension = Part.Parameter("D15@草圖1") '對應控制角度5 ^6 H( p8 f8 N# D
For i = 0.1 To 90.1 Step 5$ @% e% g9 F6 I) D0 P& j8 p
A = i * pi / 180
N! J& y% h3 V* \; q$ `myDimension.SystemValue = A
. M6 K; e( s: R. }boolstatus = Part.EditRebuild3()
1 }& y8 u* M$ S/ {3 J4 SmyModelView.RotateAboutCenter 0, 0
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For i = 85.1 To 0.05 Step -5
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* \! U6 b% x% ]6 K* DmyDimension.SystemValue = A
: k7 v. h p+ k: ^$ y5 S: Y9 `boolstatus = Part.EditRebuild3()
x6 t4 V7 N8 F& ^7 r( V% Y8 jmyModelView.RotateAboutCenter 0, 0
/ j+ Y- o6 Q7 J* HNext
3 a2 J1 Z/ r7 f* u zEnd Sub
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Macro1.rar
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发表于 2016-3-4 23:27:33
发表于 2016-3-5 07:17:16
